No. You would need to do:

(1/samples per hour) * (sum of kilowatts over period) = kilowatt-hours

i.e. (can't believe you made me type this):

(1/60) * (4.872+4.873+4.808+4.896+4.744+4.768+4.896+4.832+4.816+4.776+4.888+4.872+4.760+4.840+4.792) = 1.2kWh

This is honestly a really bad and dumb way to do this though. It is very inaccurate and if you miss any measurements your energy will be even further off. Just add the kWh register (rather than MWh) from your panel meter and calculate the difference every period - that is what it's there for!

If you ended up with 15-minute energy kWh then to get hourly energy you would just sum the kWh. Energy can be added to energy.