How to write code when get first value will be stop recevied the second value in meta ?

[edmond]

Morning.everyone.
Now I use mango received the data from equipment .and I set a meta point.the code as below,the datapoint in meta named p1.When I get the first value>2.0,I donot received the second value>2.only get first value>2 will go to end.How to write .thanks.

if (p1.value>2.0)
{
return p1.value;}
else {
return (NaN) ;
}

[edmond]

No answer? :(

[edmond]

have not answer?

why for this question for so long time and no any answer?

[JoelHaggar]

Rather than return NaN return my.value which will just returns it's current value.

[edmond]

Thanks,Joels.
In meta if I have 15 value,(I have set cron in the meta),from the 15th value start ,when 15th.value>2,then end.no need to continute 14th value. if 15th<2, then 14th value to compare with 2.if 14th.value>2 ,then end . if 14th.value<2, then 13th will compare with 2. if every value all 15 is less than 2.then will undisplay vlaue. this is my script. Is it right? Need your modify.

Thanks

var n=1
switch (n)
{
case 1:
if (p15.value>2.0)
{ return p15.value;}

break;
case 2:
if (p15.lastValue(1)>2.0)
return p1.lastValue(1);
break;
case 3:
if (p15.lastValue(2)>2.0)
return p1.lastValue(2);
break;
case 4:
if (p15.lastValue(3)>2.0)
return p1.lastValue(3);
break;
........
case15
if if (p15.lastValue(15)>2.0)
return p1.lastValue(3);
break;
return (NaN);

}