values.push(sens.prev(MINUTE, 1).firstValue)

...
values.push(sens.prev(MINUTE, n).firstValue)

thanks, this seems exactly what i need.

one other request, where do i find documentation on what you have described above e.g. prev(MINUTE,1).firstvalue - what other functions etc are there which could be used ?

So 'sens' will be our point that we want the history of.

values.push(sens.prev(MINUTE, 1).firstValue)
values.push(sens.prev(MINUTE, 2).firstValue)
values.push(sens.prev(MINUTE, 3).firstValue)
...
values.push(sens.prev(MINUTE, n).firstValue)

The best way to do this is with a meta point. Write the code necessary to get all your points into an array, here's some code I stole:

values.push(sens1.value)
...
values.push(sensN.value)

Hope that helps.

Thanks for the quick response, a clarification please :-

sens1.value 
.... 
sensN.value 

wont this be value of n different points, i need to get the last n values of the same point into the array, how can i do that ?

var myArr = new Array();
values.push(sens1.value)
...
values.push(sensN.value)
 
values.sort( function(a,b) {return a - b;} ); //works for our numeric values
 
var half = Math.floor(values.length/2);
 
if(values.length % 2)
   return values[half];
else
   return (values[half-1] + values[half]) / 2.0;

Hope that helps.